4x^2-30x-48=0

Solution for 4x^2-30x-48=0 equation:

4x^2-30x-48=0

a = 4; b = -30; c = -48;
Δ = b2-4ac
Δ = -302-4·4·(-48)
Δ = 1668
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1668}=\sqrt{4*417}=\sqrt{4}*\sqrt{417}=2\sqrt{417}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{417}}{2*4}=\frac{30-2\sqrt{417}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{417}}{2*4}=\frac{30+2\sqrt{417}}{8}
$